

Introducing your new favourite teacher - Teachoo Black, at only ₹83 per month
Miscellaneous
Misc 1 (ii)
Misc 2 (i) Important
Misc 2 (ii)
Misc 3
Misc 4
Misc 5 Important
Misc 6 Important
Misc 7 Important
Misc 8 Important
Misc 9
Misc 10 Important
Misc 11 Important
Misc 12
Misc 13 Important
Misc 14 Important
Misc 15 Important You are here
Misc 16 Important
Misc 17 (MCQ) Important
Misc 18 (MCQ)
Misc 19 (MCQ)
Last updated at Feb. 15, 2020 by Teachoo
Misc 15 An electronic assembly consists of two subsystems, say, A and B. From previous testing procedures, the following probabilities are assumed to be known: P(A fails) = 0.2 P(B fails alone) = 0.15 P(A and B fail) = 0.15 Evaluate the following probabilities (i) P(A fails |B has failed) Now, P(A fails |B has failed) = (𝑃(𝐴 & 𝐵 𝐹𝑎𝑖𝑙))/(𝑃(𝐵 𝐹𝑎𝑖𝑙)) = (0. 15)/(0. 30) = 1/2 = 0.5 ∴ P(A fails |B has failed) = 0.5 Misc 15 (ii) P(A fails alone) P(A fails alone) = P(A fails) – P(A & B fail) = 0.20 – 0.15 = 0.05