1. Chapter 13 Class 12 Probability (Term 2)
  2. Serial order wise
  3. Miscellaneous

Misc 15 - Chapter 13 Class 12 Probability (Term 2)

Last updated at Feb. 15, 2020 by

Misc 15 - An electronic assembly consists of two subsystems A, B

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Misc 15 - Chapter 13 Class 12 Probability - Part 2

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Misc 15 - Chapter 13 Class 12 Probability - Part 3

  1. Chapter 13 Class 12 Probability (Term 2)
  2. Serial order wise

    3. Miscellaneous

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Transcript

Misc 15 An electronic assembly consists of two subsystems, say, A and B. From previous testing procedures, the following probabilities are assumed to be known: P(A fails) = 0.2 P(B fails alone) = 0.15 P(A and B fail) = 0.15 Evaluate the following probabilities (i) P(A fails |B has failed) Now, P(A fails |B has failed) = (๐‘ƒ(๐ด & ๐ต ๐น๐‘Ž๐‘–๐‘™))/(๐‘ƒ(๐ต ๐น๐‘Ž๐‘–๐‘™)) = (0. 15)/(0. 30) = 1/2 = 0.5 โˆด P(A fails |B has failed) = 0.5 Misc 15 (ii) P(A fails alone) P(A fails alone) = P(A fails) โ€“ P(A & B fail) = 0.20 โ€“ 0.15 = 0.05

Chapter 13 Class 12 Probability (Term 2)
Serial order wise

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