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  1. Chapter 13 Class 12 Probability
  2. Serial order wise

Transcript

Misc 16 Bag I contains 3 red and 4 black balls and Bag II contains 4 red and 5 black balls. One ball is transferred from Bag I to Bag II and then a ball is drawn from Bag II. The ball so drawn is found to be red in color. Find the probability that the transferred ball is black. Let A : Event of drawing red ball from Bag II E1 : Event that red ball is transferred from Bag I E2 : Event that black ball is transferred from Bag I We need to find out the probability that the ball transferred is black, if ball drawn is red in color i.e. P(E2|A) P(E2|A) = (๐‘ƒ(๐ธ_2 ).๐‘ƒ(๐ด|๐ธ_2))/(๐‘ƒ(๐ธ_1 ).๐‘ƒ(๐ด|๐ธ_1)+๐‘ƒ(๐ธ_2 ).๐‘ƒ(๐ด|๐ธ_2) ) "P(E1)" = Probability that red ball is transferred from Bag I = 3/7 P(A|E1) = Probability that red ball is drawn from bag II ,if red ball is transferred from Bag I = 5/10 = 1/2 "P(E1)" = Probability that red ball is transferred from Bag I = 3/7 P(A|E1) = Probability that red ball is drawn from bag II ,if red ball is transferred from Bag I = 5/10 = 1/2 "P(E2)" = Probability that black ball is transferred from Bag I = 4/7 P(A|E2) = Probability that red ball is drawn from bag II ,if black ball is transferred from Bag I = 4/10 = 2/5 P(E2|A) = (๐‘ƒ(๐ธ_2 ).๐‘ƒ(๐ด|๐ธ_2))/(๐‘ƒ(๐ธ_1 ).๐‘ƒ(๐ด|๐ธ_1)+๐‘ƒ(๐ธ_2 ).๐‘ƒ(๐ด|๐ธ_2) ) = (4/7 ร—2/5 )/(3/7 ร—1/2 + 4/7 ร—2/5) = (8/35 )/(3/14+ 8/35) = (8/35 )/((15+16)/70 ) = (๐Ÿ๐Ÿ” )/๐Ÿ‘๐Ÿ

About the Author

Davneet Singh's photo - Teacher, Computer Engineer, Marketer
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.