# Misc 14 - Chapter 1 Class 12 Relation and Functions

Last updated at May 29, 2018 by Teachoo

Last updated at May 29, 2018 by Teachoo

Transcript

Misc 14 Define a binary operation *on the set {0, 1, 2, 3, 4, 5} as a * b = + , + <6 & + 6, + 6 Show that zero is the identity for this operation and each element a 0 of the set is invertible with 6 a being the inverse of a. e is the identity of * if a * e = e * a = a Now, we need to show that each element a 0 of the set is invertible with 6 a being the inverse of a. a * b = + , + <6 & + 6, + 6 An element a in set is invertible if, there is an element in set such that , a * b = e = b * a Putting b = 6 a So, a + b = a + (6 a) = 6 Since a + b 6 a * b = a + b 6 a * b = a * (6 a) = a + (6 a) 6 = 0 b * a = (6 a) * a = (6 a) + a 6 = 0 Since a * (6 a) = (6 a) * a = 0 Hence, each element a of the set is invertible with 6 a being the inverse of a.

Chapter 1 Class 12 Relation and Functions

Serial order wise

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.