Misc 5 - Chapter 1 Class 12 Relation and Functions (Term 1)
Last updated at May 29, 2018 by Teachoo
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Last updated at May 29, 2018 by Teachoo
Misc 5 Show that the function f: R R given by f(x) = x3 is injective. f(x) = x3 We need to check injective (one-one) f (x1) = (x1)3 f (x2) = (x2)3 Putting f (x1) = f (x2) (x1)3 = (x2)3 x1 = x2 Since if f (x1) = f (x2) , then x1 = x2 It is one-one (injective)