Question 5 - Miscellaneous - Chapter 1 Class 12 Relation and Functions
Last updated at April 16, 2024 by Teachoo
Miscellaneous
Misc 2
Misc 3 Important
Misc 4 Important
Misc 5
Misc 6 (MCQ) Important
Misc 7 (MCQ) Important
Question 1 Deleted for CBSE Board 2025 Exams
Question 2 Deleted for CBSE Board 2025 Exams
Question 3 Important Deleted for CBSE Board 2025 Exams
Question 4 Deleted for CBSE Board 2025 Exams
Question 5 Deleted for CBSE Board 2025 Exams You are here
Question 6 Important Deleted for CBSE Board 2025 Exams
Question 7 (i) Important Deleted for CBSE Board 2025 Exams
Question 7 (ii) Deleted for CBSE Board 2025 Exams
Question 8 Deleted for CBSE Board 2025 Exams
Question 9 Important Deleted for CBSE Board 2025 Exams
Question 10 Important Deleted for CBSE Board 2025 Exams
Question 11 Deleted for CBSE Board 2025 Exams
Question 12 (MCQ) Important Deleted for CBSE Board 2025 Exams
Last updated at April 16, 2024 by Teachoo
Question 5 Given examples of two functions f: N N and g: N N such that gof is onto but f is not onto. (Hint: Consider f(x) = x + 1 and g (x) = 1, >1 &1, =1 ) Let f: N N be f(x) = x + 1 And, g: N N be, g (x) = 1, >1 &1, =1 We will first show that f is not onto. Checking f is not onto f: N N be f(x) = x + 1 Let y = f(x), where y N So, y = x + 1 y 1 = x x = y 1 For y = 1, x = 1 1 = 0 But 0 is not a natural number f is not onto. Finding gof f(x) = x + 1 & g (x) = 1, >1 &1, =1 So, gof = , >1 1, =1 Let gof = y , where y N So, y = , >1 1, =1 Here y is a natural number , As y = x So, x is also a natural number Hence, gof is onto.