Ex 1.2, 4 - Show that Modulus Function f(x) = |x| is neither - Ex 1.2

part 2 - Ex 1.2 , 4 - Ex 1.2 - Serial order wise - Chapter 1 Class 12 Relation and Functions

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Ex 1.2 , 4 Show that the Modulus Function f: R → R given by f(x) =|š‘„| , is neither one-one nor onto, where |š‘„| is x, if x is positive or 0 and |š‘„| is āˆ’ x, if x is negative. f(x) =|š‘„| = {ā–ˆ( š‘„ , š‘„ā‰„0 @āˆ’š‘„ , š‘„<0)┤ Check one-one Example f (1) = |1| = 1 f (– 1) = |1| = 1 Since, different elements 1, –1, have the same image 1 , ∓ f is not one-one. Check onto f: R → R f(x) = |š‘„| Let f(x) = y such that y ∈ R y = |š‘„| Hence value of y is defined only if y is positive, But y is a real number Hence, if y is negative, there is not corresponding element of x Hence, f is not onto

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