To prove one-one & onto (injective, surjective, bijective)
To prove one-one & onto (injective, surjective, bijective)
Last updated at August 2, 2026 by Teachoo
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Ex 1.2 , 4 Show that the Modulus Function f: R ā R given by f(x) =|š„| , is neither one-one nor onto, where |š„| is x, if x is positive or 0 and |š„| is ā x, if x is negative. f(x) =|š„| = {ā( š„ , š„ā„0 @āš„ , š„<0)⤠Check one-one Example f (1) = |1| = 1 f (ā 1) = |1| = 1 Since, different elements 1, ā1, have the same image 1 , ā“ f is not one-one. Check onto f: R ā R f(x) = |š„| Let f(x) = y such that y ā R y = |š„| Hence value of y is defined only if y is positive, But y is a real number Hence, if y is negative, there is not corresponding element of x Hence, f is not onto