Ex 5.7, 1 - Find second order derivatives of x2 + 3x + 2 - Ex 5.7

part 2 - Ex 5.7, 1 - Ex 5.7 - Serial order wise - Chapter 5 Class 12 Continuity and Differentiability

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Transcript

Ex 5.7, 1 Find the second order derivatives of the function ๐‘ฅ^2 + 3๐‘ฅ + 2 Let ๐‘ฆ = ๐‘ฅ^2 + 3๐‘ฅ + 2 Differentiating ๐‘ค.๐‘Ÿ.๐‘ก.๐‘ฅ ๐‘‘๐‘ฆ/๐‘‘๐‘ฅ = (๐‘‘(๐‘ฅ^2 + 3๐‘ฅ + 2))/(๐‘‘๐‘ฅ ) ๐‘‘๐‘ฆ/๐‘‘๐‘ฅ = (๐‘‘(๐‘ฅ^2))/๐‘‘๐‘ฅ + (๐‘‘(3๐‘ฅ) )/๐‘‘๐‘ฅ + (๐‘‘(2) )/๐‘‘๐‘ฅ ๐‘‘๐‘ฆ/๐‘‘๐‘ฅ = 2๐‘ฅ+3+0 ๐’…๐’š/๐’…๐’™ = ๐Ÿ๐’™ + ๐Ÿ‘ Again Differentiating ๐‘ค.๐‘Ÿ.๐‘ก.๐‘ฅ ๐’…/๐’…๐’™ (๐’…๐’š/๐’…๐’™) = (๐’… (๐Ÿ๐’™ + ๐Ÿ‘))/๐’…๐’™ (๐‘‘^2 ๐‘ฆ)/ใ€–๐‘‘๐‘ฅใ€—^2 = ๐‘‘(2๐‘ฅ)/๐‘‘๐‘ฅ + ๐‘‘(3)/๐‘‘๐‘ฅ (๐‘‘^2 ๐‘ฆ)/ใ€–๐‘‘๐‘ฅใ€—^2 = 2 + 0 (๐’…^๐Ÿ ๐’š)/ใ€–๐’…๐’™ใ€—^๐Ÿ = 2

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