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Question 2 - Equation of line - given point and //vector - Chapter 11 Class 12 Three Dimensional Geometry
Last updated at July 21, 2026 by Teachoo
Equation of line - given point and //vector
Chapter 11 Class 12 Three Dimensional Geometry
Concept wise
- Direction cosines and ratios
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Equation of line - given point and //vector
- Equation of line - given 2 points
- Angle between two lines - Vector
- Angle between two lines - Cartisian
- Angle between two lines - Direction ratios or cosines
- Shortest distance between two skew lines
- Shortest distance between two parallel lines
- Equation of plane - In Normal Form
- Equation of plane - Prependicular to Vector & Passing Through Point
- Equation of plane - Passing Through 3 Non Collinear Points
- Equation of plane - Intercept Form
- Equation of plane - Passing Through Intersection Of Planes
- Coplanarity of 2 lines
- Angle between two planes
- Distance of point from plane
- Angle between Line and Plane
- Equation of line under planes condition
- Point with Lines and Planes
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Transcript
Question 2 The Cartesian equation of a line is + 3 2 = 5 4 = + 6 2 Find the vector equation for the line. Cartesian equation : + 3 2 = 5 4 = + 6 2 ( 3) 2 = 5 4 = ( 6) 2 Equation of a line in Cartesian form is 1 = 1 = 1 Comparing (1) and (2), 1= 3, 1= 5, 1= 6 & = 2, = 4, c = 2 Equation of line in vector form is = + where = 1 + y1 + z1 = 3 + 5 6 & = + b + c = 2 + 4 + 2 Now, = ( 3 + 5 6 ) + (2 + 4 + 2 ) Therefore, equation of line in vector form is ( 3 + 5 6 ) + (2 + 4 + 2 )
