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Ex 11.2, 6 - Chapter 11 Class 12 Three Dimensional Geometry
Last updated at August 19, 2026 by Teachoo
Equation of line - given point and //vector
Chapter 11 Class 12 Three Dimensional Geometry
Concept wise
- Direction cosines and ratios
-
Equation of line - given point and //vector
- Equation of line - given 2 points
- Angle between two lines - Vector
- Angle between two lines - Cartisian
- Angle between two lines - Direction ratios or cosines
- Shortest distance between two skew lines
- Shortest distance between two parallel lines
- Equation of plane - In Normal Form
- Equation of plane - Prependicular to Vector & Passing Through Point
- Equation of plane - Passing Through 3 Non Collinear Points
- Equation of plane - Intercept Form
- Equation of plane - Passing Through Intersection Of Planes
- Coplanarity of 2 lines
- Angle between two planes
- Distance of point from plane
- Angle between Line and Plane
- Equation of line under planes condition
- Point with Lines and Planes
Transcript
Ex 11.2, 6 Find the Cartesian equation of the line which passes through the point (โ 2, 4, โ 5) and parallel to the line given by (๐ฅ + 3)/3 = (๐ฆ โ 4)/5 = (๐ง + 8)/6. Equation of a line passing through (x1, y1, z1) and parallel to a line having direction ratios a, b, c is (๐ฅ โ ๐ฅ1)/๐ = (๐ฆ โ ๐ฆ1)/๐ = (๐ง โ ๐ง1)/๐ Since the line passes through (โ2, 4, โ5) ๐๐ = โ2, y1 = 4, z1 = โ5 Since the line is parallel to (๐ฅ + 3)/3 = (๐ฆ โ 4)/5 = (๐ง + 8)/6 ๐ = 3, b = 5, c = 6 Therefore, Equation of line in Cartesian form is (๐ฅ โ (โ2))/3 = (๐ฆ โ 4)/5 = (๐ง โ (โ5))/6 (๐ + ๐)/๐ = (๐ โ ๐)/๐ = (๐ + ๐)/๐
