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Ex 11.2, 6 - Chapter 11 Class 12 Three Dimensional Geometry
Last updated at July 21, 2026 by Teachoo
Equation of line - given point and //vector
Chapter 11 Class 12 Three Dimensional Geometry
Concept wise
- Direction cosines and ratios
-
Equation of line - given point and //vector
- Equation of line - given 2 points
- Angle between two lines - Vector
- Angle between two lines - Cartisian
- Angle between two lines - Direction ratios or cosines
- Shortest distance between two skew lines
- Shortest distance between two parallel lines
- Equation of plane - In Normal Form
- Equation of plane - Prependicular to Vector & Passing Through Point
- Equation of plane - Passing Through 3 Non Collinear Points
- Equation of plane - Intercept Form
- Equation of plane - Passing Through Intersection Of Planes
- Coplanarity of 2 lines
- Angle between two planes
- Distance of point from plane
- Angle between Line and Plane
- Equation of line under planes condition
- Point with Lines and Planes
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Transcript
Ex 11.2, 6 Find the Cartesian equation of the line which passes through the point (ā 2, 4, ā 5) and parallel to the line given by (š„ + 3)/3 = (š¦ ā 4)/5 = (š§ + 8)/6. Equation of a line passing through (x1, y1, z1) and parallel to a line having direction ratios a, b, c is (š„ ā š„1)/š = (š¦ ā š¦1)/š = (š§ ā š§1)/š Since the line passes through (ā2, 4, ā5) šš = ā2, y1 = 4, z1 = ā5 Since the line is parallel to (š„ + 3)/3 = (š¦ ā 4)/5 = (š§ + 8)/6 š = 3, b = 5, c = 6 Therefore, Equation of line in Cartesian form is (š„ ā (ā2))/3 = (š¦ ā 4)/5 = (š§ ā (ā5))/6 (š + š)/š = (š ā š)/š = (š + š)/š
