Misc 2 - Find equation of line parallel to x-axis and passing through - Miscellaneous

part 2 - Misc 2 - Miscellaneous - Serial order wise - Chapter 11 Class 12 Three Dimensional Geometry

part 3 - Misc 2 - Miscellaneous - Serial order wise - Chapter 11 Class 12 Three Dimensional Geometry part 4 - Misc 2 - Miscellaneous - Serial order wise - Chapter 11 Class 12 Three Dimensional Geometry

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Misc 2 (Introduction) Find the equation of a line parallel to x-axis and passing through the origin.Direction cosines of a line making angle š›¼ with x -axis, š›½ with y – axis and š›¾ with z – axis are l, m, n l = cos š›¼ , m = cos š›½ , n = cos š›¾ x – axis makes an angle 0° with x – axis, 90° with y – axis & 90° with z – axis. So, šœ¶ = 0°, šœ· = 90°, šœø = 90° Direction cosines are l = cos 0° , m = cos 90° , n = cos 90° l = 1 , m = 0, n = 0 ∓ Direction cosines of x – axis are 1, 0, 0. Misc 2 Find the equation of a line parallel to x-axis and passing through the origin.Equation of a line passing through (x1, y1, z1) and parallel to a line with direction ratios a, b, c is (š’™ āˆ’ š’™šŸ)/š’‚ = (š’š āˆ’ š’ššŸ)/š’ƒ = (š’› āˆ’ š’›šŸ)/š’„ Since line passes through origin ie. (0, 0, 0), x1 = 0, y1 = 0, z1 = 0 Since line is parallel to x – axis, š’‚ = 1, b = 0, c = 0 Equation of line is (š‘„ āˆ’ 0)/1 = (š‘¦ āˆ’ 0)/0 = (š‘§ āˆ’ 0)/0 š’™/šŸ = š’š/šŸŽ = š’›/šŸŽ

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