Ā
Ā
Equation of line - given point and //vector
Equation of line - given point and //vector
Last updated at July 21, 2026 by Teachoo
Ā
Ā
Transcript
Misc 2 (Introduction) Find the equation of a line parallel to x-axis and passing through the origin.Direction cosines of a line making angle š¼ with x -axis, š½ with y ā axis and š¾ with z ā axis are l, m, n l = cos š¼ , m = cos š½ , n = cos š¾ x ā axis makes an angle 0° with x ā axis, 90° with y ā axis & 90° with z ā axis. So, š¶ = 0°, š· = 90°, šø = 90° Direction cosines are l = cos 0° , m = cos 90° , n = cos 90° l = 1 , m = 0, n = 0 ā“ Direction cosines of x ā axis are 1, 0, 0. Misc 2 Find the equation of a line parallel to x-axis and passing through the origin.Equation of a line passing through (x1, y1, z1) and parallel to a line with direction ratios a, b, c is (š ā šš)/š = (š ā šš)/š = (š ā šš)/š Since line passes through origin ie. (0, 0, 0), x1 = 0, y1 = 0, z1 = 0 Since line is parallel to x ā axis, š = 1, b = 0, c = 0 Equation of line is (š„ ā 0)/1 = (š¦ ā 0)/0 = (š§ ā 0)/0 š/š = š/š = š/š