Example 19 - Find equation of plane with intercepts 2, 3, 4

Example 19 - Chapter 11 Class 12 Three Dimensional Geometry - Part 2

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Transcript

Question 9 Find the equation of the plane with intercepts 2, 3 and 4 on the x, y and z-axis respectively. The equation of a plane with intercepts ๐‘Ž, b, c on x, y, and z โ€“ axis respectively is ๐’™/๐’‚ + ๐’š/๐’ƒ + ๐’›/๐’„ = 1 Given, Intercept on x โˆ’ axis = 2 โˆด ๐‘Ž = 2 Intercept on y โˆ’ axis = 3 โˆด b = 3 Intercept on z โ€“ axis = 4 โˆด c = 4 Equation of plane is ๐’™/๐Ÿ + ๐’š/๐Ÿ‘ + ๐’›/๐Ÿ’ = 1 6๐‘ฅ/12 + 4๐‘ฆ/12 + 3๐‘ง/12 = 1 (6๐‘ฅ + 4๐‘ฆ + 3๐‘ง)/12 = 1 6x + 4y + 3z = 12

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