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Ex 11.2, 4 Find the equation of the line which passes through the point (1, 2, 3) and is parallel to the vector 3𝑖 ̂ + 2𝑗 ̂ – 2𝑘 ̂ . Equation of a line passing through a point with position vector 𝑎 ⃗, and parallel to a vector 𝑏 ⃗ is 𝒓 ⃗ = 𝒂 ⃗ + 𝜆𝒃 ⃗ Since line passes through (1, 2, 3) 𝒂 ⃗ = 1𝒊 ̂ + 2𝒋 ̂ + 3𝒌 ̂ Since line is parallel to 3𝑖 ̂ + 2𝑗 ̂ − 2𝑘 ̂ 𝒃 ⃗ = 3𝒊 ̂ + 2𝒋 ̂ − 2𝒌 ̂ Equation of line 𝑟 ⃗ = 𝑎 ⃗ + 𝜆𝑏 ⃗ 𝒓 ⃗ = (𝒊 ̂ + 2𝒋 ̂ + 3𝒌 ̂) + 𝜆 (3𝒊 ̂ + 2𝒋 ̂ − 2𝒌 ̂)

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.