Vector product - Area
Last updated at July 14, 2026 by Teachoo
Transcript
Ex 10.4, 10 Find the area of the parallelogram whose adjacent sides are determined by the vectors š ā = š Ģ ā š Ģ + 3š Ģ and b = 2š Ģ ā 7š Ģ + š Ģ . š ā = š Ģ ā š Ģ + 3š Ģ = 1š Ģ ā 1š Ģ + 3k Ģ š ā = 2š Ģ ā 7š Ģ + š Ģ = 2š Ģ ā 7š Ģ + 1k Ģ Area of parallelogram ABCD = |š ā" Ć " š ā | š ā Ć š ā = |ā 8(š Ģ&š Ģ&š Ģ@1&ā1&3@2&ā7&1)| = š Ģ (ā1 Ć 1 ā (ā7) Ć 3) ā š Ģ (1 Ć 1 ā 2 Ć 3) + š Ģ (1 Ć ā7 ā 2 Ć ā1) = š Ģ (ā1ā(ā21)) ā š Ģ (1 ā 6) + š Ģ (ā7 ā(ā2)) = š Ģ (ā1 + 21) ā š Ģ (ā5) + š Ģ (ā7 + 2) = 20 š Ģ + 5š Ģ ā 5š Ģ Magnitude of š ā Ć š ā = ā(202+52+(ā5)2) |š ā" Ć " š ā | = ā(400+25+25) = ā450 = ā(25Ć9Ć2) = 5 Ć 3 Ć ā2 = 15 ā2 Therefore, the area of parallelogram is 15āš .