Vector product - Area
Last updated at July 14, 2026 by Teachoo
Transcript
Ex 10.4, 9 Find the area of the triangle with vertices A(1, 1, 2), B(2, 3, 5) and C(1, 5, 5). A (1, 1, 2) , B (2, 3, 5) , C (1, 5, 5) Area of triangle ABC is 1/2 |(š“šµ) ā Ć (š“š¶) ā | A (1, 1, 2) B (2, 3, 5) (š“šµ) ā = (2 ā 1) š Ģ + (3 ā 1) š Ģ + (5 ā 2) š Ģ = 1š Ģ + 2š Ģ + 3š Ģ A (1, 1, 2) C (1, 5, 5) (š“š¶) ā = (1 ā 1) š Ģ + (5 ā 1) š Ģ + (5 ā 2) š Ģ = 0š Ģ + 4š Ģ + 3š Ģ (šØš©) ā Ć (šØšŖ) ā = |ā 8(š Ģ&š Ģ&š Ģ@1&2&3@0&4&3)| = š Ģ (2Ć3ā4Ć3 )āš Ģ (1Ć3ā0Ć3 )+š Ģ (1Ć4ā0Ć2 ) = š Ģ (6ā12)āš Ģ(3ā0) + š Ģ (4ā0) = ā6š Ģ ā 3š Ģ + 4š Ģ Magnitude of (š“šµ) ā Ć (š“š¶) ā = ā((ā6)2+(ā3)2+42) |(š“šµ) ā" Ć " (š“š¶) ā | = ā(36+9+16) = ā61 Area of triangle ABC = 1/2 |(š“šµ) ā" Ć " (š“š¶) ā | = 1/2 Ć ā61 = āšš/š