Ex 10.2, 1 - Compute magnitude of a = i + j + k, b = 2i -7j - 3k

Ex 10.2, 1 - Chapter 10 Class 12 Vector Algebra - Part 2

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Ex 10.2, 1 Compute the magnitude of the following vectors: ๐‘Ž โƒ— = ๐‘– ฬ‚ + ๐‘— ฬ‚ + ๐‘˜ ฬ‚, ๐‘ โƒ—= 2๐‘– ฬ‚ โˆ’ 7๐‘— ฬ‚ โ€“ 3๐‘˜ ฬ‚, ๐‘ โƒ— = 1/โˆš3 ๐‘– ฬ‚ + 1/โˆš3 ๐‘— ฬ‚ โˆ’ 1/โˆš3 ๐‘˜ ฬ‚๐‘Ž โƒ— = ๐‘– ฬ‚ + ๐‘— ฬ‚ + ๐‘˜ ฬ‚ = 1๐‘– ฬ‚ + 1๐‘— ฬ‚ + 1๐‘˜ ฬ‚ Magnitude of ๐‘Ž โƒ— = โˆš(12+12+12) |๐‘Ž โƒ— | = โˆš3 โˆด Magnitude of ๐‘Ž โƒ— = โˆš3 ๐‘ โƒ— = 2๐‘– ฬ‚ โ€“ 7๐‘— ฬ‚ โ€“ 3๐‘˜ ฬ‚ Magnitude of ๐‘ โƒ— = โˆš(22+(โˆ’7)2+(โˆ’3)2) |๐‘ โƒ— | = โˆš(4+49+9) = โˆš62 โˆด Magnitude of ๐‘ โƒ— = โˆš62 ๐‘ โƒ— = 1/โˆš3 ๐‘– ฬ‚ + 1/โˆš3 ๐‘— ฬ‚ โˆ’ 1/โˆš3 ๐‘˜ ฬ‚ Magnitude of ๐‘ โƒ— = โˆš((1/โˆš3)^2+(1/โˆš3)^2+((โˆ’1)/โˆš3)^2 ) |๐‘ โƒ— | = โˆš(1/3+1/3+1/3) = โˆš(3/3) = โˆš1 = 1 โˆด Magnitude of ๐‘ โƒ— = 1

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