Ex 10.2, 1 - Compute magnitude of a = i + j + k, b = 2i -7j - 3k

Ex 10.2, 1 - Chapter 10 Class 12 Vector Algebra - Part 2

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Ex 10.2, 1 Compute the magnitude of the following vectors: š‘Ž āƒ— = š‘– Ģ‚ + š‘— Ģ‚ + š‘˜ Ģ‚, š‘ āƒ—= 2š‘– Ģ‚ āˆ’ 7š‘— Ģ‚ – 3š‘˜ Ģ‚, š‘ āƒ— = 1/√3 š‘– Ģ‚ + 1/√3 š‘— Ģ‚ āˆ’ 1/√3 š‘˜ Ģ‚š‘Ž āƒ— = š‘– Ģ‚ + š‘— Ģ‚ + š‘˜ Ģ‚ = 1š‘– Ģ‚ + 1š‘— Ģ‚ + 1š‘˜ Ģ‚ Magnitude of š‘Ž āƒ— = √(12+12+12) |š‘Ž āƒ— | = √3 ∓ Magnitude of š‘Ž āƒ— = √3 š‘ āƒ— = 2š‘– Ģ‚ – 7š‘— Ģ‚ – 3š‘˜ Ģ‚ Magnitude of š‘ āƒ— = √(22+(āˆ’7)2+(āˆ’3)2) |š‘ āƒ— | = √(4+49+9) = √62 ∓ Magnitude of š‘ āƒ— = √62 š‘ āƒ— = 1/√3 š‘– Ģ‚ + 1/√3 š‘— Ģ‚ āˆ’ 1/√3 š‘˜ Ģ‚ Magnitude of š‘ āƒ— = √((1/√3)^2+(1/√3)^2+((āˆ’1)/√3)^2 ) |š‘ āƒ— | = √(1/3+1/3+1/3) = √(3/3) = √1 = 1 ∓ Magnitude of š‘ āƒ— = 1

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