Ex 10.2, 7 - Ex 10.2

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Ex 10.2, 7 Find the unit vector in the direction of the vector ๐‘Ž โƒ— = ๐‘– ฬ‚ + ๐‘— ฬ‚ + 2๐‘˜ ฬ‚ ๐‘Ž โƒ— = ๐‘– ฬ‚ + ๐‘— ฬ‚ + 2๐‘˜ ฬ‚, = 1๐‘– ฬ‚ + 1๐‘— ฬ‚ + 2๐‘˜ ฬ‚, Magnitude of ๐‘Ž โƒ— = โˆš(12+12+22) |๐‘Ž โƒ— | = โˆš(1+1+4) = โˆš6 Unit vector in direction of ๐‘Ž โƒ— = ๐Ÿ/|๐’‚ โƒ— | . ๐’‚ โƒ— ๐‘Ž ฬ‚ = 1/โˆš6 ["1" ๐‘– ฬ‚" + 1" ๐‘— ฬ‚" + 2" ๐‘˜ ฬ‚ ] ๐‘Ž ฬ‚ = ๐Ÿ/โˆš๐Ÿ” ๐’Š ฬ‚ + ๐Ÿ/โˆš๐Ÿ” ๐’‹ ฬ‚ + ๐Ÿ/โˆš๐Ÿ” ๐’Œ ฬ‚

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