Ex 10.2, 7 - Ex 10.2

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Ex 10.2, 7 Find the unit vector in the direction of the vector š‘Ž āƒ— = š‘– Ģ‚ + š‘— Ģ‚ + 2š‘˜ Ģ‚ š‘Ž āƒ— = š‘– Ģ‚ + š‘— Ģ‚ + 2š‘˜ Ģ‚, = 1š‘– Ģ‚ + 1š‘— Ģ‚ + 2š‘˜ Ģ‚, Magnitude of š‘Ž āƒ— = √(12+12+22) |š‘Ž āƒ— | = √(1+1+4) = √6 Unit vector in direction of š‘Ž āƒ— = šŸ/|š’‚ āƒ— | . š’‚ āƒ— š‘Ž Ģ‚ = 1/√6 ["1" š‘– Ģ‚" + 1" š‘— Ģ‚" + 2" š‘˜ Ģ‚ ] š‘Ž Ģ‚ = šŸ/āˆššŸ” š’Š Ģ‚ + šŸ/āˆššŸ” š’‹ Ģ‚ + šŸ/āˆššŸ” š’Œ Ģ‚

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