Ex 2.1, 8 - Chapter 2 Class 12 Inverse Trigonometric Functions
Last updated at July 9, 2018 by Teachoo
Transcript
Ex2.1, 8 Find the principal value of cot-1 (√3) Let y = cot-1 (√3) cot y = √3 cot y = cot π/6 Range of principal value of cot−1 is (0,π) Hence, principal value is 𝝅/𝟔 Rough We know that tan 30° = 1/√3 cot 30° = √3 θ = 30° = 30 × 𝜋/180 = 𝜋/6 Since √3 is positive Principal value is θ i.e. 𝜋/6
Chapter 2 Class 12 Inverse Trigonometric Functions
Serial order wise
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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.
