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Last updated at Feb. 13, 2020 by Teachoo
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Ex 2.1, 8 Find the principal value of cot−1 (√3) Let y = cot−1 (√3) cot y = √3 cot y = cot π/6 Range of principal value of cot−1 is (0, π) Hence, principal value is 𝝅/𝟔 Rough We know that tan 30° = 1/√3 cot 30° = √3 θ = 30° = 30 × 𝜋/180 = 𝜋/6 Since √3 is positive Principal value is θ i.e. 𝜋/6
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