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Ex 2.1, 7 - Chapter 2 Class 12 Inverse Trigonometric Functions (Term 1)

Last updated at March 16, 2023 by

Ex 2.1, 7 - Find principal value of sec-1 (2/root 3) - Chapter 2

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Ex 2.1, 7 Find the principal value of sec−1 (2/√3) Let y = sec−1 (2/√3) sec y = 2/√3 sec y = sec (𝝅/𝟔) ∴ y = 𝝅/𝟔 Since Range of sec−1 is [0, π] – {𝜋/2} Hence, Principal Value is 𝝅/𝟔 (Since sec 𝜋/6 = 2/√3)

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