Ex 2.1, 7 - Chapter 2 Class 12 Inverse Trigonometric Functions (Term 1)
Last updated at May 12, 2021 by Teachoo
Transcript
Ex 2.1, 7 Find the principal value of sec−1 (2/√3) Let y = sec−1 (2/√3) sec y = 2/√3 sec y = sec (𝝅/𝟔) ∴ y = 𝝅/𝟔 Since Range of sec−1 is [0, π] – {𝜋/2} Hence, Principal Value is 𝝅/𝟔 (Since sec 𝜋/6 = 2/√3)
Chapter 2 Class 12 Inverse Trigonometric Functions (Term 1)
Serial order wise
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