Ex 2.1, 7 - Find principal value of sec-1 (2/root 3) - Chapter 2


Ex 2.1, 7 Find the principal value of sec−1 (2/√3) Let y = sec−1 (2/√3) sec y = 2/√3 sec y = sec (𝝅/𝟔) ∴ y = 𝝅/𝟔 Since Range of sec−1 is [0, π] – {𝜋/2} Hence, Principal Value is 𝝅/𝟔 (Since sec 𝜋/6 = 2/√3)

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.