Slide7.JPG

Subscribe to our Youtube Channel - https://you.tube/teachoo

  1. Chapter 2 Class 12 Inverse Trigonometric Functions
  2. Serial order wise

Transcript

Ex 2.1, 7 Find the principal value of sec−1 (2/√3) Let y = sec−1 (2/√3) sec y = 2/√3 sec y = sec (π/6) Range of principal value of sec−1 is [0, π] – {𝜋/2} Hence, principal value of sec−1 (2/√3) is 𝝅/𝟔 Rough We know that cos 30° = √3/2 sec 30° = 2/√3 θ = 30° = 30 × 𝜋/180 = 𝜋/6 Since 2/√3 is positive Principal value is θ i.e. 𝜋/6

About the Author

Davneet Singh's photo - Teacher, Computer Engineer, Marketer
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.