Ex 2.1, 7 - Find principal value of sec-1 (2/root 3) - Chapter 2

  1. Chapter 2 Class 12 Inverse Trigonometric Functions
  2. Serial order wise

Transcript

Ex 2.1, 7 Find the principal value of sec−1 (2/√3) Let y = sec−1 (2/√3) sec y = 2/√3 sec y = sec (𝝅/𝟔) ∴ y = 𝝅/𝟔 Since Range of sec−1 is [0, π] – {𝜋/2} Hence, Principal Value is 𝝅/𝟔 (Since sec 𝜋/6 = 2/√3)

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.