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Last updated at Feb. 13, 2020 by Teachoo
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Ex 2.1, 4 Find the principal value of tan−1 (−√3) Let y = tan−1 (−√3) tan y = −√3 tan y = tan (−π/3) Range of the principal value . of tan−1 is between (−π/2 "," π/2) Hence the principal value is (−𝝅)/𝟑 Rough We know that tan 60° = √3 θ = 60° = 60° × 𝜋/180 = 𝜋/3 Since −√3 is negative Principal value is − θ i.e. (−𝜋)/3
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