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Question 11 Let P, Q be points of trisection of AB, with P closer to A, and Q closer to B. Using your knowledge of how to find the coordinates of the midpoint of a segment, how would you find the coordinates of P and Q? Do this for the case when the points are A (4, 7) and B (16, –2). Let’s draw the figure Since P & Q are points of trisection It means AP = PQ = QB Thus, AP : PQ: QB is in the ratio 1 : 1 : 1 Finding P P divides AB in the ratio 1 : 2 Now, Coordinates of P = ((1 × 16 + 2 × 4)/(1 + 2),(1 × −2 + 2 × 7)/(1 + 2)) = ((16 + 8)/3,(−2 + 14)/3) = (24/3,12/3) = (8, 4)

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Davneet Singh

Davneet Singh is an IIT Kanpur graduate and has been teaching for 16+ years. At Teachoo, he breaks down Maths, Science and Computer Science into simple steps so students understand concepts deeply and score with confidence.

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