End-of-Chapter Exercises
Last updated at April 29, 2026 by Teachoo
Transcript
Question 9 The following table shows the coordinates of points S, M and T. In each case, state whether M is the midpoint of segment ST. Justify your answer When M is the mid-point of ST, can you find any connection between the coordinates of M, S and T? For mid-point, we can do this by two ways Logically By Formula Formula for finding mid-point is Mid-point of (x1, y1) & (x2, y2) = ((π_π + π_π)/π,(π_π+π_π)/π) We do it by both methods Row 1: πΊ(βπ,π),π΄(π,π),π»(π,π). Logically Journey πβπ : You start at π₯=β3 and walk to π₯=0. That is π steps right. Journey πβπ : You start at π₯=0 and walk to π₯=3. That is also 3 steps right. Logical Answer: Yes, the steps are identical, so π is exactly in the middle. Formula Here, S (β3, 0) and T (3, 0) Mid-point of S & T = ((β3 + 3)/2,(0 + 0)/2) = (0/2,0/2) = (0, 0) This is coordinates of point M So, point M is in the middle Row 2: πΊ(π,π),π΄(π,π),π»(π,π) Logically Journey πβπ : π₯ goes from 2 to 3 (+1 step). π¦ goes from 3 to 4 (+1 step) Journey πβπ : π₯ goes from 3 to 4 (+1 step). π¦ goes from 4 to 5 (+1 step). Logical Answer: Yes, you took the exact same diagonal path both times, so π is perfectly halfway. Formula Here, S (2, 3) and T (4, 5) Mid-point of S & T = ((2 + 4)/2,(3 + 5)/2) = (6/2,8/2) = (3, 4) This is coordinates of point M So, point M is in the middle Row 3: πΊ(π,π),π΄(π,π),π»(π,βππ). Logically Journey πβπ:π¦ goes from 0 up to 5 ( π steps up). Journey πβπ : π¦ goes from 5 all the way down to -10 (15 steps down). Logical Answer: No, moving 5 steps is not the same as moving 15 steps. π is way closer to π. Formula Here, S (0, 0) and T (0, β10) Mid-point of S & T = ((0 + 0)/2,(0 +(β10))/2) = (0/2,(β10)/2) = (0, β5) This is not the coordinates of point M So, point M is not in the middle Row 4: S (-8, 7), π΄(π,βπ),π»(π,βπ) Logically Journey πβπ:π₯ goes from -8 to 0 (+8 steps horizontally). Journey πβπ : π₯ goes from 0 to 6 (+6 steps horizontally). Logical Answer: No. Since the horizontal steps don't even match ( 8 vs 6 ), π cannot be in the middle, so we don't even need to check the y -coordinates. Formula Here, S (β8, 7) and T (6, β3) Mid-point of S & T = ((β8 + 6)/2,(7 + (β3))/2) = ((β(8 β 6) )/2,(7 β 3)/2) = ((β2)/2,4/2) = (β1, 2) This is not the coordinates of point M So, point M is not in the middle The Connection (Midpoint Formula): To find the midpoint, you simply average the x coordinates and average the y βcoordinates of points S (x1, y1) and T (x2, y2) Coordinates of M = ((π_π + π_π)/π,(π_π+π_π)/π)