Slide48.JPG

Slide49.JPG
Slide50.JPG Slide51.JPG

Remove Ads Share on WhatsApp

Transcript

Question 8 (i) Using the origin as one vertex, plot the vertices of: (i) A right-angled isosceles triangle. Since it is a right-angled isosceles triangle, we Draw a vertical line of distance 5 And a horizontal line of same distance 5 Thus, ∆ AOB is the required right isosceles triangle with OA = OB = 5 units ∠ AOB = 90° Question 8 (ii) An isosceles triangle with one vertex in Quadrant III and the other in Quadrant IV. Here, we choose a point and then draw a mirror image Let’s choose one point in Quadrant III as (–5, –4) Then its mirror image in Quadrant IV is (5, –4) Thus, ∆ AOB is the required isosceles triangle with OM = ON (their distance would be equal by distance formula)

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh is an IIT Kanpur graduate and has been teaching for 16+ years. At Teachoo, he breaks down Maths, Science and Computer Science into simple steps so students understand concepts deeply and score with confidence.

Many students prefer Teachoo Black for a smooth, ad-free learning experience.