End-of-Chapter Exercises
Last updated at April 29, 2026 by Teachoo
Transcript
Question 8 (i) Using the origin as one vertex, plot the vertices of: (i) A right-angled isosceles triangle. Since it is a right-angled isosceles triangle, we Draw a vertical line of distance 5 And a horizontal line of same distance 5 Thus, ∆ AOB is the required right isosceles triangle with OA = OB = 5 units ∠ AOB = 90° Question 8 (ii) An isosceles triangle with one vertex in Quadrant III and the other in Quadrant IV. Here, we choose a point and then draw a mirror image Let’s choose one point in Quadrant III as (–5, –4) Then its mirror image in Quadrant IV is (5, –4) Thus, ∆ AOB is the required isosceles triangle with OM = ON (their distance would be equal by distance formula)