Question 6 - Figure it out - Page 28, 29, 30 - Chapter 1 Class 8 - Fractions in Disguise (Ganita Prakash II)

Transcript

Question 6 What percentage of area is occupied by the region marked ‘E’ in the figure?We can write Percentage of Area as Percentage of Area occupied by E = (𝑨𝒓𝒆𝒂 𝒐𝒇 𝑬)/(𝑻𝒐𝒕𝒂𝒍 𝑨𝒓𝒆𝒂) × 100 We assume length between each dot is 1 unit Finding both areas Total Area It is a square with Side = 8 units Now, Total Area = Area of square of side 8 units = 8 × 8 = 64 square units Area of E It is a Right angled triangle with Height = 4 units Base = 4 units Now, Total Area = Area of right angled triangle = 𝟏/𝟐 × Base × Height = 1/2 × 4 × 4 = 2 × 4 = 8 square units Now, Percentage of Area occupied by E = (𝐴𝑟𝑒𝑎 𝑜𝑓 𝐸)/(𝑇𝑜𝑡𝑎𝑙 𝐴𝑟𝑒𝑎) × 100 = 𝟖/𝟔𝟒 × 100 = 1/8 × 100 = 1/2 × 25 = 12.5%