Depreciation - Definition, Formula, Questions - Teachoo Maths - Depreciation

part 2 - Depreciation - Depreciation - Chapter 1 Class 8 - Fractions in Disguise (Ganita Prakash II) - Class 8 (Ganita Prakash - 1, 2 & Old NCERT)
part 3 - Depreciation - Depreciation - Chapter 1 Class 8 - Fractions in Disguise (Ganita Prakash II) - Class 8 (Ganita Prakash - 1, 2 & Old NCERT) part 4 - Depreciation - Depreciation - Chapter 1 Class 8 - Fractions in Disguise (Ganita Prakash II) - Class 8 (Ganita Prakash - 1, 2 & Old NCERT)

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DepreciationWhile money in the bank grows, physical things you buy usually lose their value over time as they get older and used. This loss of value is called Depreciation. It is basically the exact opposite of compound interest. Here is the formula for Depreciation: 𝑉=𝑃(1βˆ’π‘Ÿ)^𝑑 Here is the formula for Depreciation: 𝑽=𝑷(πŸβˆ’π’“)^𝒕 Let's define our terms: 𝑽= Current Value (what it's worth now) 𝑷= Initial Price (what you bought it for) 𝒓= Rate of depreciation (as a decimal) 𝒕= Time in years Notice it's almost the exact same formula as compound interest, but we use a minus sign because the value is shrinking, not growing! Let’s do an example Real-Life Example: Buying a Car Cars are famous for depreciating. Let's say you buy a brand-new Tata Curvv for road trips, and it costs β‚Ή15,00,000. On average, cars lose about 10% of their value every year due to depreciation. What will your car be worth after 𝟐 years? Our values are Initial Price = P = β‚Ή 15,00,000 Rate = R = 10% per year = 10/100 = 1/10 Time = T = 2 years Now, Current Value = 𝑽=𝑷(πŸβˆ’π’“)^𝒕 = 15,00,000 Γ— (1βˆ’1/10)^3 = 15,00,000 Γ— ((10 βˆ’ 1)/10)^3 = πŸπŸ“,𝟎𝟎,𝟎𝟎𝟎 Γ— (πŸ—/𝟏𝟎)^πŸ‘ = 15,00,000 Γ—729/1000 = 1,500 Γ— 729 = 12,15,000 Thus, after just two years, the car's value has depreciated down to β‚Ή12,15,000.

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CA Maninder Singh

CA Maninder Singh is a Chartered Accountant for the past 16 years. He also provides Accounts Tax GST Training in Delhi, Kerala and online.