Evaluate the following: 3Γ·7/9, 14/4Γ·2, 2/3Γ·2/3, 14/6Γ·7/3, 4/3Γ·3/4 - Figure it out - Page 196 to 198

part 2 - Question 1 - Figure it out - Page 196 to 198 - Chapter 8 Class 7 - Working with Fractions (Ganita Prakash) - Class 7 (Ganita Prakash 1, 2 & old NCERT)
part 3 - Question 1 - Figure it out - Page 196 to 198 - Chapter 8 Class 7 - Working with Fractions (Ganita Prakash) - Class 7 (Ganita Prakash 1, 2 & old NCERT) part 4 - Question 1 - Figure it out - Page 196 to 198 - Chapter 8 Class 7 - Working with Fractions (Ganita Prakash) - Class 7 (Ganita Prakash 1, 2 & old NCERT) part 5 - Question 1 - Figure it out - Page 196 to 198 - Chapter 8 Class 7 - Working with Fractions (Ganita Prakash) - Class 7 (Ganita Prakash 1, 2 & old NCERT) part 6 - Question 1 - Figure it out - Page 196 to 198 - Chapter 8 Class 7 - Working with Fractions (Ganita Prakash) - Class 7 (Ganita Prakash 1, 2 & old NCERT) part 7 - Question 1 - Figure it out - Page 196 to 198 - Chapter 8 Class 7 - Working with Fractions (Ganita Prakash) - Class 7 (Ganita Prakash 1, 2 & old NCERT)

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Transcript

Question 1 Evaluate the following: Let’s do one by one 3 Γ· πŸ•/πŸ— = 3 Γ— 9/7 = (3 Γ— 9)/7 = πŸπŸ•/πŸ• πŸπŸ’/πŸ’ Γ· 2 = 14/4 Γ— 1/2 = (14 Γ— 1)/(4 Γ— 2) = (7 Γ— 1)/(2 Γ— 2) = πŸ•/πŸ’ 𝟐/πŸ‘ Γ· 𝟐/πŸ‘ = 2/3 Γ— 3/2 = (2 Γ— 3)/(3 Γ— 2) = 1 πŸπŸ’/πŸ” Γ· πŸ•/πŸ‘ = 14/6 Γ— 3/7 = (14 Γ— 3)/(6 Γ— 7) = (2 Γ— 3)/(6 Γ— 1) = (2 Γ— 1)/(2 Γ— 1) = 1 πŸ’/πŸ‘ Γ· πŸ‘/πŸ’ = 4/3 Γ— 4/3 = (4 Γ— 4)/(3 Γ— 3) = πŸπŸ”/πŸ— πŸ•/πŸ’ Γ· 𝟏/πŸ• = 7/4 Γ— 7/1 = (7 Γ— 7)/(4 Γ— 1) = πŸ’πŸ—/πŸ’ πŸ–/𝟐 Γ· πŸ’/πŸπŸ“ = 8/2 Γ— 15/4 = (8 Γ— 15)/(2 Γ— 4) = (4 Γ— 15)/(1 Γ— 4) = (1 Γ— 15)/(1 Γ— 1) = 15 𝟏/πŸ“ Γ· 𝟏/πŸ— = 1/5 Γ— 9/1 = (1 Γ— 9)/(5 Γ— 1) = πŸ—/πŸ“ 𝟏/πŸ” Γ· 𝟏𝟏/𝟏𝟐 = 1/6 Γ— 12/11 = (1 Γ— 12)/(6 Γ— 11) = (1 Γ— 2)/(1 Γ— 11) = 𝟐/𝟏𝟏 πŸ‘ 𝟐/πŸ‘ Γ· 𝟏 πŸ‘/πŸ– First we convert into normal fractions πŸ‘ 𝟐/πŸ‘ = 3+2/3=(3 Γ— 3 + 2)/3=(9 + 2)/3=𝟏𝟏/πŸ‘ 𝟏 πŸ‘/πŸ– = 1+3/8=(1 Γ— 8 + 3)/8=(8 + 3)/8=𝟏𝟏/πŸ– Now, πŸ‘ 𝟐/πŸ‘ Γ· 𝟏 πŸ‘/πŸ– = 𝟏𝟏/πŸ‘Γ·πŸπŸ/πŸ– =11/3 Γ—8/11 =(11 Γ— 8)/(3 Γ— 11) =(1 Γ— 8)/(3 Γ— 1) = πŸ–/πŸ‘

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