Check sibling questions

Ex 10.1, 11 - Slope of a line is double of slope of another

Ex 10.1, 11 - Chapter 10 Class 11 Straight Lines - Part 2
Ex 10.1, 11 - Chapter 10 Class 11 Straight Lines - Part 3

This video is only available for Teachoo black users

Solve all your doubts with Teachoo Black (new monthly pack available now!)


Transcript

Ex 10.1, 11 The slope of a line is double of the slope of another line. If tangent of the angle between them is 1/3 , find the slopes of the lines. Let m1 & m2 be the slopes of two lines We know that angles between two lines are tan θ = |(𝑚2 − 𝑚1)/(1 + 𝑚1𝑚2)| Here tan θ = 1/3 & m2 = 2m1 Putting values tan θ = |(𝑚2 − 𝑚1)/(1 + 𝑚1𝑚2)| 1/3 = |(2𝑚1 − 𝑚1)/(1 + 𝑚1(2𝑚1))| 1/3 = |𝑚_1/(1 + 2〖𝑚_1〗^2 )| |𝑚_1/(1 + 2〖𝑚_1〗^2 )| = 1/3 So, 𝑚_1/(1 + 2〖𝑚_1〗^2 ) = 1/3 or 𝑚_1/(1 + 2〖𝑚_1〗^2 ) = ( −1)/3 Solving 𝒎_𝟏/(𝟏 + 𝟐〖𝒎_𝟏〗^𝟐 ) = 𝟏/𝟑 3m1 = 1 + 2〖"m1" 〗^2 2〖"m1" 〗^2 + 1 – 3m1 = 0 2〖"m1" 〗^2 – 3m1 + 1 = 0 2〖"m1" 〗^2 – 2m1 – m1 + 1 = 0 2m1(m1 – 1) – 1(m1 – 1) = 0 (2m1 – 1) (m1 – 1) = 0 So, m1 = 𝟏/𝟐 , m1 = 1 Solving 𝒎_𝟏/(𝟏 + 𝟐〖𝒎_𝟏〗^𝟐 ) = (−𝟏)/𝟑 3m1 = –1 – 2〖"m1" 〗^2 2〖"m1" 〗^2 + 1 + 3m1 = 0 2〖"m1" 〗^2 + 3m1 + 1 = 0 2〖"m1" 〗^2 + 2m1 + m1 + 1 = 0 2m1(m1 + 1) + 1(m1 + 1) = 0 (2m1 + 1) (m1 + 1) = 0 So, m1 = (−𝟏)/𝟐 , m1 = –1 When m1 = ( 𝟏)/𝟐 m2 = 2m1 m2 = 2(1/2) = 1 When m1 = 1 m2 = 2m1 m2 = 2(1) = 2 When m1 = ( −𝟏)/𝟐 m2 = 2m1 m2 = 2(( − 1)/2) = –1 When m1 = –1 m2 = 2m1 m2 = 2(−1) = –2 Hence slope of lines are 𝟏/𝟐 and 1 or 1 and 2 or ( −𝟏)/𝟐 and −1 or −1 and −2

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.