Ex 10.1, 10 - Find angle between x-axis and line joining - Slope - Finding slope

  1. Chapter 10 Class 11 Straight Lines
  2. Serial order wise
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Ex10.1, 10 Find the angle between the x-axis and the line joining the points (3, –1) and (4, –2). First we find slope of line joining the points (3, –1) and (4, –2). We know that slope of line passing through (x1, y1) and (x2, y2) is m = (𝑦_2 − 𝑦_1)/(𝑥_2 − 𝑥_1 ) Here x1 = 3, y1 = –1 & x2 = 4, y2 = –2 Slope of line joining (3, –1) and (4, –2) is m = ( − 2 − ( − 1))/(4 − 3) = ( − 2 + 1)/(4 − 3) = ( − 1)/1 = –1 Now, Slope = m = tan θ where θ is the angle between line and positive x-axis So m = tan θ –1 = tan θ tan θ = –1 tan θ = tan (135°) θ = 135° So, Required angle = θ = 135°

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  • Dev San's image
     theta is taken in 2 quadrant as tan has negative value... can it be taken in 4 quadrant as tan is also negative in 4 quadrant also..



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  • Pulkit Singla's image
    class 11th. maths ncert. ex 10.1  . question 10 : if tan is negative in the 2nd and the 4rth quadrants , then why answer is given only for 2nd quadrant?

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