Ex 10.1, 8 - Find value of x for which points (x, -1) - Ex 10.1

Ex 10.1, 8 - Chapter 10 Class 11 Straight Lines - Part 2
Ex 10.1, 8 - Chapter 10 Class 11 Straight Lines - Part 3

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Transcript

Ex10.1, 8 Find the value of x for which the points (x, –1), (2, 1) and (4, 5) are collinear. Let the three points be A (x, –1) , B (2, 1) , C (4, 5) If 3 points are collinear Slope of AB = Slope of BC We know that slope of a line through the points (x1, y1)(x2, y2)is m = (𝑦2 − 𝑦1)/(𝑥2 − 𝑥1) 2 = 4 – 2x 2 – 4 = -2x -2 = -2x ( − 2 )/( − 2) = x 1 = x x = 1 Hence value of x is 1

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.