![Ex 10.1, 8 - Chapter 10 Class 11 Straight Lines - Part 2](https://d1avenlh0i1xmr.cloudfront.net/9aa1d15d-5bfe-4da2-9e66-1ca6ebbc1ef1/slide23.jpg)
![Ex 10.1, 8 - Chapter 10 Class 11 Straight Lines - Part 3](https://d1avenlh0i1xmr.cloudfront.net/5a5a9758-6968-4b08-878d-d76f2d72759f/slide24.jpg)
Ex 9.1
Last updated at April 16, 2024 by Teachoo
Ex10.1, 8 Find the value of x for which the points (x, –1), (2, 1) and (4, 5) are collinear. Let the three points be A (x, –1) , B (2, 1) , C (4, 5) If 3 points are collinear Slope of AB = Slope of BC We know that slope of a line through the points (x1, y1)(x2, y2)is m = (𝑦2 − 𝑦1)/(𝑥2 − 𝑥1) 2 = 4 – 2x 2 – 4 = -2x -2 = -2x ( − 2 )/( − 2) = x 1 = x x = 1 Hence value of x is 1