Ex 10.1, 5 - Find slope of a line, which passes through origin - Ex 10.1

  1. Chapter 10 Class 11 Straight Lines
  2. Serial order wise
Ask Download

Transcript

Ex10.1, 5 Find the slope of a line, which passes through the origin, and the mid-point of the line segment joining the points P (0, –4) and B (8, 0). We need to find Slope of a line passing through origin O(0, 0) & mid point of P (0, –4) & B(8, 0) Let M be the mid point of P (0, –4) & B(8, 0) We know that mid point of (x1, y1) and (x2, y2) = ((𝑥1 + 𝑥2 )/2,(𝑦1 + 𝑦2)/2) Mid point M of (0, –4) & (8, 0) = ((0 + 8)/2, ( − 4 + 0)/2) = (8/2, (−4)/2) = (4, –2) We know that slope of line passing through (x1, y1) and (x2, y2) is m = (𝑦_2 − 𝑦_1)/(𝑥_2 − 𝑥_1 ) Slope of line between points O(0, 0) & M(4, –2) Here x1 = 0 , y1 = 0 x2 = 4 , y2 = –2 Putting values m = ( − 2 − 0)/(4 − 0) = ( − 2)/4 = ( − 1)/2 Hence slope of line is ( − 1)/2

About the Author

Davneet Singh's photo - Teacher, Computer Engineer, Marketer
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.