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Question 37 (ii) What is the area of the watered region (in terms of 𝝅)?Radius (r) = 21 m And, 𝜽=𝟖𝟎° Area of watered region = Area of sector with angle 80° = 𝜃/(360°)× 𝜋𝑟2 = (𝟖𝟎°)/(𝟑𝟔𝟎° )× 𝝅 × (𝟐𝟏)𝟐 = 8/36× 𝜋 × 441 = 2/9× 𝜋 × 441 = 2 × 𝜋 × 49 = 98𝝅 m2

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 15 years. He provides courses for Maths, Science and Computer Science at Teachoo