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Question 37 (Case Based Questions) A water sprinkler is a device used to irrigate agricultural crops, lawns, landscapes, golf courses, and other areas. Water sprinklers can be used for residential, industrial, and agricultural usage. A water sprinkler is set to shoot a stream of water a distance of 21m and rotate through an angle which is equal to complementary angle of 10°.Given that A water sprinkler is set to shoot a stream of water a distance of 21 m and rotate through an angle which is equal to complementary angle of 10° So, Radius = 21 m Angle = 𝜃 = Complementary of 10° Given that A water sprinkler is set to shoot a stream of water a distance of 21 m and rotate through an angle which is equal to complementary angle of 10° So, Radius = 21 m Angle = 𝜃 = Complementary of 10° = 90° – 10° = 80° So, our diagram looks like r = 21 m Question 37 (i) What is the area of sector in terms of arc length?We know that Area of sector = 𝜽/(𝟑𝟔𝟎°)× 𝝅𝒓𝟐 Arc length = 𝜽/(𝟑𝟔𝟎°)× 𝟐𝝅𝒓 Now, writing Arc length as Arc length = 𝜃/(360°)× 𝜋𝑟 × 2 1/2 × Arc length = 𝜃/(360°)× 𝜋𝑟 𝜽/(𝟑𝟔𝟎°)× 𝝅𝒓 = 𝟏/𝟐 × Arc length Now, Area of sector = 𝜃/(360°)× 𝜋𝑟2 Area of sector = 𝜃/(360°)× 𝜋𝑟 ×𝑟 Putting 𝜃/(360°)× 𝜋𝑟 = 1/2 × Arc length Area of sector = 1/2 × Arc length × 𝑟 Area of sector = 𝟏/𝟐 × Arc length × Radius

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 15 years. He provides courses for Maths, Science and Computer Science at Teachoo