




CBSE Class 10 Sample Paper for 2026 Boards - Maths Basic
CBSE Class 10 Sample Paper for 2026 Boards - Maths Basic
Last updated at Sept. 10, 2025 by Teachoo
Transcript
Question 37 (Case Based Questions) A water sprinkler is a device used to irrigate agricultural crops, lawns, landscapes, golf courses, and other areas. Water sprinklers can be used for residential, industrial, and agricultural usage. A water sprinkler is set to shoot a stream of water a distance of 21m and rotate through an angle which is equal to complementary angle of 10°.Given that A water sprinkler is set to shoot a stream of water a distance of 21 m and rotate through an angle which is equal to complementary angle of 10° So, Radius = 21 m Angle = 𝜃 = Complementary of 10° Given that A water sprinkler is set to shoot a stream of water a distance of 21 m and rotate through an angle which is equal to complementary angle of 10° So, Radius = 21 m Angle = 𝜃 = Complementary of 10° = 90° – 10° = 80° So, our diagram looks like r = 21 m Question 37 (i) What is the area of sector in terms of arc length?We know that Area of sector = 𝜽/(𝟑𝟔𝟎°)× 𝝅𝒓𝟐 Arc length = 𝜽/(𝟑𝟔𝟎°)× 𝟐𝝅𝒓 Now, writing Arc length as Arc length = 𝜃/(360°)× 𝜋𝑟 × 2 1/2 × Arc length = 𝜃/(360°)× 𝜋𝑟 𝜽/(𝟑𝟔𝟎°)× 𝝅𝒓 = 𝟏/𝟐 × Arc length Now, Area of sector = 𝜃/(360°)× 𝜋𝑟2 Area of sector = 𝜃/(360°)× 𝜋𝑟 ×𝑟 Putting 𝜃/(360°)× 𝜋𝑟 = 1/2 × Arc length Area of sector = 1/2 × Arc length × 𝑟 Area of sector = 𝟏/𝟐 × Arc length × Radius