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Question 28 A quadrilateral ABCD is drawn to circumscribe a circle, as shown in the given figure. Show that "AB + CD" /"AD + BC" "= 1"We know that, Lengths of tangents drawn from external point are equal So, AP = AS BP = BQ CR = CQ DR = DS Adding all the above equations AP + BP + CR + DR = AS + BQ + CQ + DS Grouping them (AP + BP) + (CR + DR) = (AS + DS) + (BQ + CQ) AB + CD = AD + BC Dividing (𝑨𝑩+𝑪𝑫)/(𝑨𝑫+𝑩𝑪)=𝟏 Hence proved

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 15 years. He provides courses for Maths, Science and Computer Science at Teachoo