This Page is Locked

Get access to this page and all premium solutions, videos, and worksheets by joining Teachoo Black.

  • ✅ 100% Ad-free learning
  • ✅ HD video solutions in Hinglish
  • ✅ Worksheets & Sample Papers
  • ✅ Step-by-step explanations
  • ✅ Access on any device
Unlock All Content (less than ₹2/day)
Trusted by thousands of parents & students
Remove Ads

Transcript

Question 26 Show that √2−√5 is an irrational number. We have to prove √2 − √5 is irrational Let us assume the opposite, i.e., √𝟐 − √𝟓 is rational Hence, √2 − √5 can be written in the form 𝑎/𝑏 where a and b (b≠ 0) are co-prime (no common factor other than 1) Hence, √𝟐 − √𝟓 = 𝒂/𝒃 Squaring both sides (√𝟐−√𝟓)^𝟐 =𝒂^𝟐/𝒃^𝟐 (√2)^2+(√5)^2−2 ×√2 ×√5=𝑎^2/𝑏^2 2+5−2 × √(2 × 5)=𝑎^2/𝑏^2 𝟕−𝟐 × √𝟏𝟎=𝒂^𝟐/𝒃^𝟐 −2 × √10=𝑎^2/𝑏^2 −7 √10=1/(−2) (𝑎^2/𝑏^2 −7) √𝟏𝟎=(−𝟏)/𝟐 (𝒂^𝟐/𝒃^𝟐 −𝟕) Here, (−1)/2 (𝑎^2/𝑏^2 −7) is a rational number But √10 is irrational Since, Rational ≠ Irrational This is a contradiction ∴ Our assumption is incorrect Therefore, √2−√5 is irrational Hence proved.

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 15 years. He provides courses for Maths, Science and Computer Science at Teachoo