If sin 𝒙 = 7/25 , where π‘₯ is an acute angle, then find the value of - CBSE Class 10 Sample Paper for 2026 Boards - Maths Basic

part 2 - Question 25 (B) - CBSE Class 10 Sample Paper for 2026 Boards - Maths Basic - Solutions of Sample Papers for Class 10 Boards - Class 10

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Question 25 (B) If sin 𝒙 = 7/25 , where π‘₯ is an acute angle, then find the value of sin𝒙. cos𝒙(tan𝒙 + cot𝒙).Now, we need to find 𝐬𝐒𝐧⁑𝒙 πœπ¨π¬β‘π’™ (π­πšπ§β‘π’™+πœπ¨π­β‘π’™ ) Putting tan x and cot x in terms of sin and cos Our equation becomes 𝐬𝐒𝐧⁑𝒙 πœπ¨π¬β‘π’™ (π­πšπ§β‘π’™+πœπ¨π­β‘π’™ ) =𝑠𝑖𝑛⁑π‘₯ π‘π‘œπ‘ β‘π‘₯ ((𝑠𝑖𝑛 π‘₯)/(π‘π‘œπ‘  π‘₯)+(π‘π‘œπ‘  π‘₯)/(𝑠𝑖𝑛 π‘₯)) =𝑠𝑖𝑛⁑π‘₯ π‘π‘œπ‘ β‘π‘₯ ((𝑠𝑖𝑛 π‘₯ Γ—sin⁑π‘₯ + cos⁑π‘₯ Γ—cos⁑π‘₯ )/(sin⁑π‘₯ Γ— π‘π‘œπ‘  π‘₯)) =π’”π’Šπ’β‘π’™ 𝒄𝒐𝒔⁑𝒙 ((〖𝐬𝐒𝐧〗^πŸβ‘π’™ + γ€–πœπ¨π¬γ€—^πŸβ‘π’™)/(π’”π’Šπ’β‘π’™ Γ— 𝒄𝒐𝒔 𝒙)) Putting sin^2⁑π‘₯ + cos^2⁑π‘₯=1 =𝑠𝑖𝑛⁑π‘₯ π‘π‘œπ‘ β‘π‘₯ (1/(sin⁑π‘₯ Γ— π‘π‘œπ‘  π‘₯)) =𝟏 Thus, answer is 1

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 15 years. He provides courses for Maths, Science and Computer Science at Teachoo