
CBSE Class 10 Sample Paper for 2026 Boards - Maths Basic
CBSE Class 10 Sample Paper for 2026 Boards - Maths Basic
Last updated at Sept. 9, 2025 by Teachoo
Transcript
Question 21 (B) Find the smallest number which is divisible by both 306 and 657.Smallest number divisible by both 306 and 657 is their LCM Note: You can take numbers like 2 & 5 and check. So, smallest number divisible by 2 & 5 is 10. Which is their LCM. (HCF of 2 & 5 is 1) Finding LCM of 306 & 657 Thus, L.C.M = 2 × 3 × 3 × 17 × 73 = 22338 Thus, required number is 22338