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Question 21 (B) Find the smallest number which is divisible by both 306 and 657.Smallest number divisible by both 306 and 657 is their LCM Note: You can take numbers like 2 & 5 and check. So, smallest number divisible by 2 & 5 is 10. Which is their LCM. (HCF of 2 & 5 is 1) Finding LCM of 306 & 657 Thus, L.C.M = 2 × 3 × 3 × 17 × 73 = 22338 Thus, required number is 22338

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 15 years. He provides courses for Maths, Science and Computer Science at Teachoo