In the given figure, PA is a tangent from an external point P to - CBSE Class 10 Sample Paper for 2026 Boards - Maths Basic

part 2 - Question 16 - CBSE Class 10 Sample Paper for 2026 Boards - Maths Basic - Solutions of Sample Papers for Class 10 Boards - Class 10

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Question 16 In the given figure, PA is a tangent from an external point P to a circle with centre O and diameter AB. If ∠POB = 115°, then measure of ∠APO is (A) 25° (B) 30° (C) 20° (D) 65°Since AB is a straight line By linear pair ∠ AOP + ∠ POB = 180° ∠ AOP + 115° = 180° ∠ AOP = 180° – 115° ∠ AOP = 65° Also, we know that Tangent is perpendicular to the radius, ∴ OA ⊥ AP So, ∠ PAO = 90° Now, in ∆ APO By angle sum property ∠ AOP + ∠ PAO + ∠ APO = 180° Putting values 65° + 90° + ∠ APO = 180° 155° + ∠ APO = 180° ∠ APO = 180° – 155° ∠ APO = 25° So, correct answer is (a)

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 15 years. He provides courses for Maths, Science and Computer Science at Teachoo