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Question 16 In the given figure, PA is a tangent from an external point P to a circle with centre O and diameter AB. If ∠POB = 115°, then measure of ∠APO is (A) 25° (B) 30° (C) 20° (D) 65°Since AB is a straight line By linear pair ∠ AOP + ∠ POB = 180° ∠ AOP + 115° = 180° ∠ AOP = 180° – 115° ∠ AOP = 65° Also, we know that Tangent is perpendicular to the radius, ∴ OA ⊥ AP So, ∠ PAO = 90° Now, in ∆ APO By angle sum property ∠ AOP + ∠ PAO + ∠ APO = 180° Putting values 65° + 90° + ∠ APO = 180° 155° + ∠ APO = 180° ∠ APO = 180° – 155° ∠ APO = 25° So, correct answer is (a)

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 15 years. He provides courses for Maths, Science and Computer Science at Teachoo