CBSE Class 10 Sample Paper for 2026 Boards - Maths Basic
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CBSE Class 10 Sample Paper for 2026 Boards - Maths Basic
Last updated at September 9, 2025 by Teachoo
Transcript
Question 15 From an external point Q, the length of tangent to a circle is 12 cm and the distance of Q from the centre of circle is 13 cm. The radius of circle (in cm) is (A) 10 (B) 5 (C) 12 (D) 7Given PQ = 12 cm & OQ = 13 cm We need to find radius of circle i.e. OP We know that Tangent is perpendicular to the radius, ∴ OP ⊥ XY So, ∠ OPY = 90° ΔOPQ is a right angled triangle Using Pythagoras theorem (Hypotenuse)2 = (Height)2 + (Base)2 OQ2 = OP2 + PQ2 (13)2 = OP2 + (12)2 OP2 = (13)2 – (12)2 OP2 = 169 – 144 OP2 = 25 OP = √25 OP= √(5^2 ) OP = 5 cm Hence, radius = OP = 5 cm So, correct answer is (b)
