This question is similar to CBSE Class 10 Sample Paper for 2020 Boards - Maths Standard
Please check the question here
https://www.teachoo.com/10979/3130/Question-13/category/CBSE-Class-10-Sample-Paper-for-2020-Boards---Maths-Standard/

CBSE Class 10 Sample Paper for 2026 Boards - Maths Basic
CBSE Class 10 Sample Paper for 2026 Boards - Maths Basic
Last updated at Sept. 9, 2025 by Teachoo
This question is similar to CBSE Class 10 Sample Paper for 2020 Boards - Maths Standard
Please check the question here
https://www.teachoo.com/10979/3130/Question-13/category/CBSE-Class-10-Sample-Paper-for-2020-Boards---Maths-Standard/
Transcript
Question 10 If βABC ~ βPQR, then perimeter of the triangle PQR (in cm) is (A) 12 (B) 24 (C) 18 (D) 20If two triangles are similar, Then their sides and perimeter are proportional So, we can write (π·ππππππππ ππ βπ¨π©πͺ)/(π·ππππππππ ππ βπ·πΈπΉ)=π¨π©/π·πΈ=π¨πͺ/π·πΉ=π©πͺ/πΈπΉ Since we know AC and PR (πππππππ‘ππ ππ βπ΄π΅πΆ)/(πππππππ‘ππ ππ βπππ )=π΄πΆ/ππ Putting values (π + π + π)/(π·ππππππππ ππ βπ·πΈπΉ)=π/ππ ππ/(π·ππππππππ ππ βπ·πΈπΉ)=π/π 12 Γ 2 = Perimeter of β PQR 24 = Perimeter of β PQR Perimeter of β PQR = 24 cm So, correct answer is (b)