Ex 3.3, 17 - Prove sin 5x + sin 3x / cos 5x + cos 3x = tan 4x - Ex 3.3

part 2 - Ex 3.3, 17 - Ex 3.3 - Serial order wise - Chapter 3 Class 11 Trigonometric Functions

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Ex 3.3, 17 Prove that ๐‘ ๐‘–๐‘›โกใ€–5๐‘ฅ + ๐‘ ๐‘–๐‘›โก3๐‘ฅ ใ€—/๐‘๐‘œ๐‘ โกใ€–5๐‘ฅ + ๐‘๐‘œ๐‘ โก3๐‘ฅ ใ€— = tan 4x Solving L.H.S. ๐‘ ๐‘–๐‘›โกใ€–5๐‘ฅ + ๐‘ ๐‘–๐‘›โก3๐‘ฅ ใ€—/๐‘๐‘œ๐‘ โกใ€–5๐‘ฅ + ๐‘๐‘œ๐‘ โก3๐‘ฅ ใ€— We solve sin 5x + sin 3x & cos 5x + cos 3x seperately sin 5x + sin 3x = 2 sin ((5x+3x)/2) cos ((5xโˆ’3x)/2) = 2 sin (8๐‘ฅ/2) cos (2๐‘ฅ/2) = 2 sin 4x cos x cos 5x + cos 3x = 2 cos ((5x+3x)/2) cos ((5xโˆ’3x)/2) = 2 cos (8๐‘ฅ/2) cos (2๐‘ฅ/2) = 2 cos 4x cos (x) Now ๐’”๐’Š๐’โกใ€–๐Ÿ“๐’™ + ๐’”๐’Š๐’โก๐Ÿ‘๐’™ ใ€—/๐’„๐’๐’”โกใ€–๐Ÿ“๐’™ + ๐’„๐’๐’”โก๐Ÿ‘๐’™ ใ€— = (2 ใ€– ๐‘ ๐‘–๐‘› ใ€—โกใ€–4x ๐‘๐‘œ๐‘ โก๐‘ฅ ใ€—)/(2 ๐‘๐‘œ๐‘ โกใ€– 4๐‘ฅ ๐‘๐‘œ๐‘ โก๐‘ฅ ใ€— ) = ๐’”๐’Š๐’โกใ€– ๐Ÿ’๐’™ใ€—/๐œ๐จ๐ฌโกใ€– ๐Ÿ’๐’™ใ€— = tan 4x = R.H.S Hence L.H.S = R.H.S Hence proved

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