Question 10 - Sample Paper 2 by Teachoo - Teachoo Sample Paper

What will be the output of the following code:

n = 3

for i in range(n):

  for j in range(n-i):

    print(j+1, end="")

  print()

Options:

a)123

   12

   1

b)321

   21

   1

c)123

   23

   3

d) None of the above

Answer:

Answer by student

a) 123

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     12

     1

Detailed answer by teachoo

Let’s go through each of the options and see why they are correct or incorrect.

• Option a: 123 12 1

This option is correct . The code uses a nested for loop to print the numbers from 1 to n-i in each line, where n is 3 and i is the outer loop variable. The outer loop runs from 0 to 2, and the inner loop runs from 0 to n-i-1. In each iteration of the inner loop, the value of j+1 is printed without a newline, and after the inner loop ends, a newline is printed. Here is how the output is generated:

• When i = 0, the inner loop runs from 0 to 2, and prints j+1 as 1, 2, and 3. Then a newline is printed.

• When i = 1, the inner loop runs from 0 to 1, and prints j+1 as 1 and 2. Then a newline is printed.

• When i = 2, the inner loop runs from 0 to 0, and prints j+1 as 1. Then a newline is printed.

• Option b: 321 21 1

This option is incorrect . The code does not print the numbers in reverse order in each line. To do that, we would need to change the inner loop to run from n-i-1 to -1 with a negative step of -1, and print j+1 as n-i-j.

• Option c: 123 23 3

This option is incorrect . The code does not skip the first i numbers in each line. To do that, we would need to change the inner loop to run from i to n-1, and print j+1 as j-i+1.

• Option d: None of the above

This option is incorrect . There is an option that matches the output of the code, which is option a.

So, the correct answer is option a.

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