What will be the output of the following Python code?

d = {"a": 1, "b": 2, "c": 3}

d.pop("b")

print(d)

print(d.popitem())

print(d)

A) {"a": 1, "c": 3}

   ("c", 3)

   {"a": 1}

B) {"a": 1, "c": 3}

   ("a", 1)

   {"c": 3}

C) {"a": 1, "b": 2}

   ("c", 3)

   {"a": 1, "b": 2}

D) KeyError

Answer:

Answer by student

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A) {"a": 1, "c": 3}

   ("c", 3)

   {"a": 1}

Detailed answer by teachoo

  • The code creates a dictionary d with three key-value pairs: “a”: 1, “b”: 2, and “c”: 3.
  • The pop() method removes and returns the value associated with the given key from the dictionary. If the key is not found, it raises a KeyError . In this case, the key “b” is found and its value 2 is removed and returned. The dictionary d is updated to {“a”: 1, “c”: 3}.
  • The print(d) statement prints the updated dictionary {“a”: 1, “c”: 3}.
  • The popitem() method removes and returns an arbitrary key-value pair from the dictionary as a tuple. If the dictionary is empty, it raises a KeyError . In this case, the dictionary d is not empty and one of its key-value pairs is removed and returned. The order of removal is not guaranteed, but in this example, we assume that the pair (“c”, 3) is removed and returned. The dictionary d is updated to {“a”: 1}.
  • The print(d.popitem()) statement prints the removed pair (“c”, 3) as a tuple.
  • The print(d) statement prints the updated dictionary {“a”: 1}.

So, the correct answer is option A.

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