What will be the output of the following Python code?
d = {"a": 1, "b": 2, "c": 3}
d.pop("b")
print(d)
print(d.popitem())
print(d)
A) {"a": 1, "c": 3}
("c", 3)
{"a": 1}
B) {"a": 1, "c": 3}
("a", 1)
{"c": 3}
C) {"a": 1, "b": 2}
("c", 3)
{"a": 1, "b": 2}
D) KeyError
Answer:
Answer by student
-lock-
A) {"a": 1, "c": 3}
("c", 3)
{"a": 1}
Detailed answer by teachoo
- The code creates a dictionary d with three key-value pairs: “a”: 1, “b”: 2, and “c”: 3.
- The pop() method removes and returns the value associated with the given key from the dictionary. If the key is not found, it raises a KeyError . In this case, the key “b” is found and its value 2 is removed and returned. The dictionary d is updated to {“a”: 1, “c”: 3}.
- The print(d) statement prints the updated dictionary {“a”: 1, “c”: 3}.
- The popitem() method removes and returns an arbitrary key-value pair from the dictionary as a tuple. If the dictionary is empty, it raises a KeyError . In this case, the dictionary d is not empty and one of its key-value pairs is removed and returned. The order of removal is not guaranteed, but in this example, we assume that the pair (“c”, 3) is removed and returned. The dictionary d is updated to {“a”: 1}.
- The print(d.popitem()) statement prints the removed pair (“c”, 3) as a tuple.
- The print(d) statement prints the updated dictionary {“a”: 1}.
So, the correct answer is option A.
-endlock-