Ex 3.2, 9 - Chapter 3 Class 11 Trigonometric Functions

Last updated at Dec. 13, 2024 by Teachoo

Ex 3.2, 9 - Find value of sin -11pi/3 - Chapter 3 Class 11 - Teachoo - Ex 3.2

part 2 - Ex 3.2, 9 - Ex 3.2 - Serial order wise - Chapter 3 Class 11 Trigonometric Functions

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Transcript

Ex 3.2,9 Find the value of the trigonometric function sin (–11"π" /3) sin ((−𝟏𝟏 𝝅)/𝟑) = –sin ((11 𝜋)/3) = –sin ("3 " 𝟐/𝟑 " π" ) = –sin ("4π – " 𝟏/𝟑 " π" ) = –sin ((−𝟏)/𝟑 " π" ) Rough So, 11/3 = 3 2/3 = 3 + 2/3 or 4 – 1/3 We take 4 – 𝟏/𝟑 as it is even = – ("–sin " (1/3 " π" )) = sin (𝟏/𝟑 " π" ) = sin 60° = √𝟑/𝟐

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo

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