Ex 3.1, 6 - If in two circles, arcs of same length subtend - Ex 3.1

part 2 - Ex 3.1, 6 - Ex 3.1 - Serial order wise - Chapter 3 Class 11 Trigonometric Functions
part 3 - Ex 3.1, 6 - Ex 3.1 - Serial order wise - Chapter 3 Class 11 Trigonometric Functions Ā 

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Ex 3.1, 6 If in two circles, arcs of the same length subtend angles 60° and 75° at the centre, find the ratio of their radii. We know that š‘™ = r Īø Let the radius of the two circles be r1 and r2 Length of arc of 1st Circle š‘™ = r1 Īø = r1 Ɨ 60° Converting into radians = r1 Ɨ 60° Ɨ šœ‹/(180°) = r1 Ɨ š…/šŸ‘ Length of arc of 2nd circle š‘™ = r2 Īø = r2 Ɨ 75° Converting into radians = r2 Ɨ 75° Ɨ šœ‹/(180°) = r2 Ɨ šŸ“š…/šŸšŸ Given that Length of 1st arc = length of 2nd arc r1 Ɨ š…/šŸ‘ = r2 Ɨ šŸ“š…/šŸšŸ š‘Ÿ1/š‘Ÿ2 = 5šœ‹/12 Ɨ 3/šœ‹ š’“šŸ/š’“šŸ = šŸ“/šŸ’ Hence, r1 : r2 = 22 : 13 So, Ratio of Radius = 5 : 4

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