Ex 3.1, 5 - In a circle of diameter 40 cm, length of a chord - Ex 3.1

part 2 - Ex 3.1, 5 - Ex 3.1 - Serial order wise - Chapter 3 Class 11 Trigonometric Functions
part 3 - Ex 3.1, 5 - Ex 3.1 - Serial order wise - Chapter 3 Class 11 Trigonometric Functions  

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Ex 3.1, 5 In a circle of diameter 40 cm, the length of a chord is 20 cm. Find the length of minor arc of the chord. Given Diameter = 40 cm Radius = r = 20 cm We need to find length of minor arc of the chord. Thus, we use formula Īø = š’/š’“ to find length of arc In figure, AB = r = 20 cm AC = r = 20 cm BC = Length of chord = 20 cm So, AB = AC = BC = 20 cm Since all sides of Ī” ABC are equal Hence, Ī” ABC is equilateral Since in equilateral triangle, all angles are 60° Hence, ∠ BAC is 60° ∓ šœ½ = 60° Finding Angle in Radians Now, Īø = 60o = 60o Ɨ šœ‹/(180°) = š…/šŸ‘ Now, Putting values in formula "Īø = " š’/š’“ š…/šŸ‘ =š’/šŸšŸŽ š‘™ = 20 Ɨ (šœ‹ )/3 š’ = (šŸšŸŽš… )/šŸ‘ cm

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