Ex 3.1, 5 - In a circle of diameter 40 cm, length of a chord - Ex 3.1

part 2 - Ex 3.1, 5 - Ex 3.1 - Serial order wise - Chapter 3 Class 11 Trigonometric Functions
part 3 - Ex 3.1, 5 - Ex 3.1 - Serial order wise - Chapter 3 Class 11 Trigonometric Functions ย 

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Transcript

Ex 3.1, 5 In a circle of diameter 40 cm, the length of a chord is 20 cm. Find the length of minor arc of the chord. Given Diameter = 40 cm Radius = r = 20 cm We need to find length of minor arc of the chord. Thus, we use formula ฮธ = ๐’/๐’“ to find length of arc In figure, AB = r = 20 cm AC = r = 20 cm BC = Length of chord = 20 cm So, AB = AC = BC = 20 cm Since all sides of ฮ” ABC are equal Hence, ฮ” ABC is equilateral Since in equilateral triangle, all angles are 60ยฐ Hence, โˆ  BAC is 60ยฐ โˆด ๐œฝ = 60ยฐ Finding Angle in Radians Now, ฮธ = 60o = 60o ร— ๐œ‹/(180ยฐ) = ๐…/๐Ÿ‘ Now, Putting values in formula "ฮธ = " ๐’/๐’“ ๐…/๐Ÿ‘ =๐’/๐Ÿ๐ŸŽ ๐‘™ = 20 ร— (๐œ‹ )/3 ๐’ = (๐Ÿ๐ŸŽ๐… )/๐Ÿ‘ cm

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