Example 5 - If arcs of same lengths in two circles subtend - Examples

part 2 - Example 5 - Examples - Serial order wise - Chapter 3 Class 11 Trigonometric Functions
part 3 - Example 5 - Examples - Serial order wise - Chapter 3 Class 11 Trigonometric Functions

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Example 5 If the arcs of the same lengths in two circles subtend angles 65° and 110° at the center, find the ratio of their radii. We know that š‘™ = r Īø Let the radius of the two circles be r1 and r2 Length of arc of 1st Circle š‘™ = r1 Īø = r1 Ɨ 65° Converting into radians = r1 Ɨ 65° Ɨ šœ‹/(180°) = r1 Ɨ šŸšŸ‘š…/šŸ‘šŸ” Length of arc of 2nd circle š‘™ = r2 Īø = r2 Ɨ 110° Converting into radians = r2 Ɨ 110° Ɨ šœ‹/(180°) = r2 Ɨ šŸšŸš…/šŸšŸ– Given that Length of 1st arc = length of 2nd arc r1 Ɨ šŸšŸ‘š…/šŸ‘šŸ” = r2 Ɨ šŸšŸš…/šŸšŸ– š‘Ÿ1/š‘Ÿ2 = 11šœ‹/18 Ɨ 36/13šœ‹ š‘Ÿ1/š‘Ÿ2 = 22šœ‹/13šœ‹ š’“šŸ/š’“šŸ = šŸšŸ/šŸšŸ‘ Hence, r1 : r2 = 22 : 13 So, Ratio of Radius = 22 : 13

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