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Question 3 - Examples - Chapter 12 Class 10 Surface Areas and Volumes

Last updated at May 29, 2023 by

Example 10 - A copper rod of diameter 1 cm, length 8 cm - Conversion of one shape to another

Example 10 - Chapter 13 Class 10 Surface Areas and Volumes - Part 2
Example 10 - Chapter 13 Class 10 Surface Areas and Volumes - Part 3 Example 10 - Chapter 13 Class 10 Surface Areas and Volumes - Part 4

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Question 3 A copper rod of diameter 1 cm and length 8 cm is drawn into a wire of length 18 m of uniform thickness. Find the thickness of the wire. Volume of copper rod = Volume of wire Volume of copper rod Copper rod is in form of cylinder with Diameter of rod = 1 cm So, radius = r = 1/2 cm And, length = height = h = 8 cm Volume of copper rod = 2 = (1/2)^2 8 = 1/4 8 = 2 cm3 Volume of wire Wire is form of cylinder with radius = r length = height = h = 18 m = 18 100 = 1800 cm Volume of wire = 2 = 2 1800 = 1800 2 cm2 Now, Volume of copper rod = Volume of wire 1800 2=2 1800 2=2 r2 = 2/1800 r2 = 2/1800 r2 = 1/900 r = (1/900) r = (1/(30 30)) r = (1/ 30 ^2 ) r = 1/30 So, r = 1/30 cm Thickness of wire = Diameter of wire = 2r = 2 1/30 = 1/15 cm

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