Examples

Example 1

Example 2 Important

Example 3 Important

Example 4

Example 5

Example 6 Important You are here

Example 7 Important

Example 8

Example 9 Important

Example 10

Example 11 Important

Example 12 Important Deleted for CBSE Board 2022 Exams

Example 13 Deleted for CBSE Board 2022 Exams

Example 14 Deleted for CBSE Board 2022 Exams

Surface Area and Volume Formulas Important

Chapter 13 Class 10 Surface Areas and Volumes (Term 2)

Serial order wise

Last updated at Feb. 25, 2017 by Teachoo

Example 6 A juice seller was serving his customers using glasses as shown in figure. The inner diameter of the cylindrical glass was 5 cm, but the bottom of the glass had a hemispherical raised portion which reduced the capacity of the glass. If the height of a glass was 10 cm, find the apparent capacity of the glass and its actual capacity. (Use = 3.14.) Apparent capacity of the glass = Volume of cylinder Actual capacity of the glass = Volume of cylinder volume of hemisphere Volume of cylinder Given inner diameter of the glass = 5 cm So, radius = r = /2 "=" 5/2 = 2.5 cm Height = 10 cm Volume of the cylindrical glass = 2 = 3.14 (2.5)2 10 = 3.14 2.5 2.5 10 = 3.14 6.25 10 = 196.25 cm3 Volume of the hemisphere Radius of hemisphere = r = 2.5 cm Volume of the hemisphere = 2/3 r3 = 2/3 3.14 (2.5)3 = 2/3 3.14 2.5 2.5 2.5 = 2/3 3.14 15.62 = 32.7 cm3 Now, Apparent capacity of the glass = Volume of cylinder = 196.25 cm3 Actual capacity of the glass = Total volume of cylinder volume of hemisphere = 196.25 32.7 = 163.54cm3 Hence, apparent capacity = 196.25cm3 Actual capacity of the glass = 163.54cm3