1. Chapter 13 Class 10 Surface Areas and Volumes
  2. Serial order wise
  3. Ex 13.4

Ex 13.4, 1 - Class 10

Last updated at May 29, 2018 by

Ex 13.4, 1 - A drinking glass is in shape of a frustum - Frustum of a cone - Volume

  1. Chapter 13 Class 10 Surface Areas and Volumes
  2. Serial order wise
    3. Ex 13.4
    Examples →
Ask Download

Transcript

Ex 13.4, 1 A drinking glass is in the shape of a frustum of a cone of height 14 cm. The diameters of its two circular ends are 4 cm and 2 cm. Find the capacity of the glass. Since glass is in from of frustum Capacity of glass = Volume of frustum = 1/3 ๐œ‹โ„Ž(๐‘Ÿ12+๐‘Ÿ22+๐‘Ÿ1๐‘Ÿ2) Hence , h = height of frustum = 14 cm r1 = (๐ท๐‘–๐‘Ž๐‘š๐‘’๐‘ก๐‘’๐‘Ÿ ๐‘œ๐‘“ 1^๐‘ ๐‘ก ๐‘’๐‘›๐‘‘)/2 = 4/2 = 2 cm r2 = (๐ท๐‘–๐‘Ž๐‘š๐‘’๐‘ก๐‘’๐‘Ÿ ๐‘œ๐‘“ 2^๐‘›๐‘‘ ๐‘’๐‘›๐‘‘)/2 = 2/2 = 1 cm Volume of glass = 1/3 ๐œ‹โ„Ž(๐‘Ÿ12+๐‘Ÿ22+๐‘Ÿ1๐‘Ÿ2) = 1/3ร—22/7ร—14(22+12+2ร—1) = 1/3 ร— 22ร—2(4+1+2) = (22 ร— 2 ร— 7)/3 = 308/3 = 102.6 cm3 Hence, volume of glass = 102.6 cm3

Chapter 13 Class 10 Surface Areas and Volumes
Serial order wise

About the Author

Davneet Singh's photo - Teacher, Computer Engineer, Marketer
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.