Ex 13.4, 1 - A drinking glass is in shape of a frustum - Frustum of a cone - Volume

Ex 13.4, 1 - Chapter 13 Class 10 Surface Areas and Volumes - Part 2

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Transcript

Question 1 A drinking glass is in the shape of a frustum of a cone of height 14 cm. The diameters of its two circular ends are 4 cm and 2 cm. Find the capacity of the glass. Since glass is in from of frustum Capacity of glass = Volume of frustum = 1/3 𝜋ℎ(𝑟12+𝑟22+𝑟1𝑟2) Hence , h = height of frustum = 14 cm r1 = (𝐷𝑖𝑎𝑚𝑒𝑡𝑒𝑟 𝑜𝑓 1^𝑠𝑡 𝑒𝑛𝑑)/2 = 4/2 = 2 cm r2 = (𝐷𝑖𝑎𝑚𝑒𝑡𝑒𝑟 𝑜𝑓 2^𝑛𝑑 𝑒𝑛𝑑)/2 = 2/2 = 1 cm Volume of glass = 1/3 𝜋ℎ(𝑟12+𝑟22+𝑟1𝑟2) = 1/3×22/7×14(22+12+2×1) = 1/3 × 22×2(4+1+2) = (22 × 2 × 7)/3 = 308/3 = 102.66 cm3 Hence, volume of glass = 102.66 cm3

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.