Check sibling questions

Ex 13.3, 1 - A metallic sphere of radius 4.2 cm is melted - Conversion of one shape to another

Ex 13.3, 1 - Chapter 13 Class 10 Surface Areas and Volumes - Part 2
Ex 13.3, 1 - Chapter 13 Class 10 Surface Areas and Volumes - Part 3

This video is only available for Teachoo black users

Solve all your doubts with Teachoo Black (new monthly pack available now!)


Transcript

Ex 13.3, 1 A metallic sphere of radius 4.2 cm is melted and recast into the shape of a cylinder of radius 6 cm. Find the height of the cylinder. Since sphere is melted into a cylinder , So, Volume of sphere = volume of cylinder Volume of sphere Radius = r = 4.2 cm volume of sphere = 4/3 𝜋𝑟3 = 4/3 𝜋(4.2)3 Volume of cylinder Radius = r = 6 cm Let height = h cm Volume of cylinder = 𝜋𝑟2ℎ = 𝜋×6^2×ℎ = 36𝜋h Now, Volume of sphere = Volume of cylinder 4/3 𝜋(4.2)3= 36𝜋h 4/3 𝜋(4.2)3×1/36𝜋 = h h = 4/3 𝜋(4.2)3×1/36𝜋 h = 4/3×(4.2)3×1/36 h = 4/3×4.2×4.2×4.2×1/36 h = (4.2 × 4.2 × 4.2)/27 h = (4.2 × 4.2 × 4.2)/(3 × 3 × 3) h = 1.4 × 1.4 × 1.4 h = 2.744 cm Hence, height of cylinder = 2.744 cm

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.