1. Chapter 13 Class 10 Surface Areas and Volumes
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  3. Ex 13.3

Ex 13.3, 6 - Class 10

Last updated at May 29, 2018 by

Ex 13.3, 6 - How many silver coins, 1.75 cm in diameter - Conversion of one shape to another


 

  1. Chapter 13 Class 10 Surface Areas and Volumes
  2. Serial order wise
    3. Ex 13.3
    Ex 13.4 →
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Ex 13.3, 6 How many silver coins, 1.75 cm in diameter and of thickness 2 mm, must be melted to form a cuboid of dimensions 5.5 cm Γ— 10 cm Γ— 3.5 cm? Number of coins = (π‘‰π‘œπ‘™π‘’π‘šπ‘’ π‘œπ‘“ π‘π‘’π‘π‘œπ‘–π‘‘)/(π‘‰π‘œπ‘™π‘’π‘šπ‘’ π‘œπ‘“ 1 π‘π‘œπ‘–π‘›) Volume of cuboid Length (l) = 5.5 cm Breadth (b) = 10 cm Height (h) = 3.5 cm Volume of cuboid = π‘™π‘β„Ž = 5.5 Γ—10Γ—3.5 = 192.5 cm3 Volume of 1 coin Coin is in shape of cylinder with Diameter = 1.75 cm Radius = Diameteπ‘Ÿ/2 = 1.75/2 cm= 0.875 cm = 875/1000 cm Height = 2 mm = 2 Γ— 1/10 cm = 2/10 cm Volume of 1 coin = πœ‹π‘Ÿ2β„Ž = 22/7Γ—(875/1000)^2Γ— 2/10 = 22/7Γ—875/1000 Γ—875/1000Γ—0.2 = 0.48125 cm3 Number of coins = (π‘‰π‘œπ‘™π‘’π‘šπ‘’ π‘œπ‘“ π‘π‘’π‘π‘œπ‘–π‘‘)/(π‘‰π‘œπ‘™π‘’π‘šπ‘’ π‘œπ‘“ 1 π‘π‘œπ‘–π‘›) = 192.5/0.48125 = 1925/4.8125 = 19250000/48125 = 400 Hence, number of coins = 400

Chapter 13 Class 10 Surface Areas and Volumes
Serial order wise

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.